Baby Afghan for Carman's baby

This pattern is in sets of 12 chains. Meaning that 14 chain stitches between the repeat of the pattern exists. In the afghan shown, there is 15 sets of 12 chain stitches. At the end of the line, you will add 2 chains. 

1. Chain 12 = 1 set, repeat Chain 12 over and over until you get your desired width. This aghan has a total of 15 Sets. At the desired length, add 3 stitches. 
2. Skip 3 CH (counts as 1 DC), 1 DC into the next CH, * 1 DC into the next 3 CH, using next 2 stitches create DC2TOG, using next 2 stitches create DC2TOG, 1 DC into the next 3 CH, 2DC in the next 2 chain, 2 DC in the next 2 chain. Repeat from * all the way to the end. End last stitch with 2DC. 
3. CH 3 (counts as 1 DC), 1 DC into the 1st stitch. *1 DC into the next 3 stitches, Using next 2 stitches create DC2TOG, using next 2 stitches create DC2TOG. 1 DC into each of the next 3 stitches, Next two stitches get 2DC each, repeat from * all the way to the end. Final stitch ends with 2DC.  
4. Repeat step 2 and 3 until you get your desired length. 
5. Fasten off. 

Read more: http://thecrochetcrowd.com/baby-lazy-wave-afghan.html#ixzz1mgDTTVRV